101131403 has 2 divisors, whose sum is σ = 101131404. Its totient is φ = 101131402.

The previous prime is 101131363. The next prime is 101131417. The reversal of 101131403 is 304131101.

It is an a-pointer prime, because the next prime (101131417) can be obtained adding 101131403 to its sum of digits (14).

It is a strong prime.

It is an emirp because it is prime and its reverse (304131101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101131403 - 2⁶ = 101131339 is a prime.

It is a Sophie Germain prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (101131463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50565701 + 50565702.

It is an arithmetic number, because the mean of its divisors is an integer number (50565702).

Almost surely, 2^101131403 is an apocalyptic number.

101131403 is a deficient number, since it is larger than the sum of its proper divisors (1).

101131403 is an equidigital number, since it uses as much as digits as its factorization.

101131403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 101131403 is about 10056.4110397298. The cubic root of 101131403 is about 465.9028253110.

Adding to 101131403 its reverse (304131101), we get a palindrome (405262504).

The spelling of 101131403 in words is "one hundred one million, one hundred thirty-one thousand, four hundred three".