Base | Representation |
---|---|
bin | 101111000101111110… |
… | …0011001010110110010 |
3 | 100200001001220122210001 |
4 | 1132023330121112302 |
5 | 3124104310111310 |
6 | 114243124100214 |
7 | 10210101531313 |
oct | 1361374312662 |
9 | 320031818701 |
10 | 101132113330 |
11 | 39987494656 |
12 | 17724b3466a |
13 | 96c92252a1 |
14 | 4c7555c60a |
15 | 296d81593a |
hex | 178bf195b2 |
101132113330 has 16 divisors (see below), whose sum is σ = 182709535104. Its totient is φ = 40303571760.
The previous prime is 101132113301. The next prime is 101132113349. The reversal of 101132113330 is 33311231101.
It is a junction number, because it is equal to n+sod(n) for n = 101132113298 and 101132113307.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18656352 + ... + 18661771.
It is an arithmetic number, because the mean of its divisors is an integer number (11419345944).
Almost surely, 2101132113330 is an apocalyptic number.
101132113330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
101132113330 is a deficient number, since it is larger than the sum of its proper divisors (81577421774).
101132113330 is a wasteful number, since it uses less digits than its factorization.
101132113330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 37318401.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 101132113330 its reverse (33311231101), we get a palindrome (134443344431).
The spelling of 101132113330 in words is "one hundred one billion, one hundred thirty-two million, one hundred thirteen thousand, three hundred thirty".
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