1011321214433 has 2 divisors, whose sum is σ = 1011321214434. Its totient is φ = 1011321214432.

The previous prime is 1011321214427. The next prime is 1011321214459. The reversal of 1011321214433 is 3344121231101.

It is an a-pointer prime, because the next prime (1011321214459) can be obtained adding 1011321214433 to its sum of digits (26).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 621081119569 + 390240094864 = 788087^2 + 624692^2 .

It is a cyclic number.

It is not a de Polignac number, because 1011321214433 - 2⁶ = 1011321214369 is a prime.

It is a super-2 number, since 2×1011321214433² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1011321214333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505660607216 + 505660607217.

It is an arithmetic number, because the mean of its divisors is an integer number (505660607217).

Almost surely, 2^{1011321214433} is an apocalyptic number.

It is an amenable number.

1011321214433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011321214433 is an equidigital number, since it uses as much as digits as its factorization.

1011321214433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 1011321214433 its reverse (3344121231101), we get a palindrome (4355442445534).

The spelling of 1011321214433 in words is "one trillion, eleven billion, three hundred twenty-one million, two hundred fourteen thousand, four hundred thirty-three".