101132131122 has 64 divisors (see below), whose sum is σ = 245493763200. Its totient is φ = 30605480640.

The previous prime is 101132131109. The next prime is 101132131157. The reversal of 101132131122 is 221131231101.

101132131122 is a `hidden beast` number, since 1 + 0 + 11 + 321 + 311 + 22 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 101132131095 and 101132131104.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 337204 + ... + 562112.

It is an arithmetic number, because the mean of its divisors is an integer number (3835840050).

Almost surely, 2^101132131122 is an apocalyptic number.

It is a practical number, because each smaller number is the sum of distinct divisors of 101132131122, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (122746881600).

101132131122 is an abundant number, since it is smaller than the sum of its proper divisors (144361632078).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101132131122 is a wasteful number, since it uses less digits than its factorization.

101132131122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 225688 (or 225682 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 101132131122 its reverse (221131231101), we get a palindrome (322263362223).

The spelling of 101132131122 in words is "one hundred one billion, one hundred thirty-two million, one hundred thirty-one thousand, one hundred twenty-two".