101132210113333 has 8 divisors (see below), whose sum is σ = 115579815785280. Its totient is φ = 86684641212480.

The previous prime is 101132210113307. The next prime is 101132210113379. The reversal of 101132210113333 is 333311012231101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 101132210113333 - 2⁵ = 101132210113301 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101132210113298 and 101132210113307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101132210113303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3023188 + ... + 14539741.

It is an arithmetic number, because the mean of its divisors is an integer number (14447476973160).

Almost surely, 2^{101132210113333} is an apocalyptic number.

It is an amenable number.

101132210113333 is a deficient number, since it is larger than the sum of its proper divisors (14447605671947).

101132210113333 is an equidigital number, since it uses as much as digits as its factorization.

101132210113333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18385547.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 101132210113333 its reverse (333311012231101), we get a palindrome (434443222344434).

The spelling of 101132210113333 in words is "one hundred one trillion, one hundred thirty-two billion, two hundred ten million, one hundred thirteen thousand, three hundred thirty-three".