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101132210120093 is a prime number
BaseRepresentation
bin10110111111101010101101…
…011101011010010110011101
3111021002010220121101221012022
4112333222231131122112131
5101223422231242320333
6555031255042545525
730205363305314405
oct2677525535322635
9437063817357168
10101132210120093
112a250a25113129
12b4141246682a5
13445795a14c079
141ad8b7a077805
15ba5a32e14c98
hex5bfaad75a59d

101132210120093 has 2 divisors, whose sum is σ = 101132210120094. Its totient is φ = 101132210120092.

The previous prime is 101132210120069. The next prime is 101132210120147. The reversal of 101132210120093 is 390021012231101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 100560041929369 + 572168190724 = 10027963^2 + 756418^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-101132210120093 is a prime.

It is a super-3 number, since 3×1011322101200933 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101132210120003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50566105060046 + 50566105060047.

It is an arithmetic number, because the mean of its divisors is an integer number (50566105060047).

Almost surely, 2101132210120093 is an apocalyptic number.

It is an amenable number.

101132210120093 is a deficient number, since it is larger than the sum of its proper divisors (1).

101132210120093 is an equidigital number, since it uses as much as digits as its factorization.

101132210120093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 26.

Adding to 101132210120093 its reverse (390021012231101), we get a palindrome (491153222351194).

The spelling of 101132210120093 in words is "one hundred one trillion, one hundred thirty-two billion, two hundred ten million, one hundred twenty thousand, ninety-three".