10113233112133 has 4 divisors (see below), whose sum is σ = 10113276506560. Its totient is φ = 10113189717708.

The previous prime is 10113233112121. The next prime is 10113233112179. The reversal of 10113233112133 is 33121133231101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10113233112133 - 2³⁷ = 9975794158661 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10113233112098 and 10113233112107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10113233182133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21345735 + ... + 21814372.

It is an arithmetic number, because the mean of its divisors is an integer number (2528319126640).

Almost surely, 2^{10113233112133} is an apocalyptic number.

It is an amenable number.

10113233112133 is a deficient number, since it is larger than the sum of its proper divisors (43394427).

10113233112133 is an equidigital number, since it uses as much as digits as its factorization.

10113233112133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43394426.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 10113233112133 its reverse (33121133231101), we get a palindrome (43234366343234).

The spelling of 10113233112133 in words is "ten trillion, one hundred thirteen billion, two hundred thirty-three million, one hundred twelve thousand, one hundred thirty-three".