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10113301131300 = 223252113199499711
BaseRepresentation
bin1001001100101010111110…
…1110001011000000100100
31022210211012100022002000200
42103022233232023000210
52311144020042200200
633301553021310500
72062443013151253
oct223125756130044
938724170262020
1010113301131300
11324a032920a14
121174038105430
135848ac542653
1426d6b490479a
1512810bc63800
hex932afb8b024

10113301131300 has 216 divisors, whose sum is σ = 32140876185600. Its totient is φ = 2659576550400.

The previous prime is 10113301131287. The next prime is 10113301131431. The reversal of 10113301131300 is 313110331101.

10113301131300 is a `hidden beast` number, since 1 + 0 + 1 + 1 + 330 + 1 + 1 + 31 + 300 = 666.

10113301131300 is a nontrivial binomial coefficient, being equal to C(4497400, 2).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 19988445 + ... + 20488155.

Almost surely, 210113301131300 is an apocalyptic number.

10113301131300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

10113301131300 is the 4497399-th triangular number and also the 2248700-th hexagonal number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 10113301131300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16070438092800).

10113301131300 is an abundant number, since it is smaller than the sum of its proper divisors (22027575054300).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10113301131300 is a wasteful number, since it uses less digits than its factorization.

10113301131300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 500043 (or 500033 counting only the distinct ones).

The product of its (nonzero) digits is 81, while the sum is 18.

Adding to 10113301131300 its reverse (313110331101), we get a palindrome (10426411462401).

It can be divided in two parts, 10113301 and 131300, that added together give a triangular number (10244601 = T4526).

The spelling of 10113301131300 in words is "ten trillion, one hundred thirteen billion, three hundred one million, one hundred thirty-one thousand, three hundred".