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1011330121303 is a prime number
BaseRepresentation
bin11101011011101111111…
…10001111111001010111
310120200102100001020000101
432231313332033321113
5113032201002340203
62052333150154531
7133031463123445
oct16556776177127
93520370036011
101011330121303
1135a9a2540807
121440044b2a47
13744a2709228
1436d3d0cbb95
151b4912b441d
hexeb77f8fe57

1011330121303 has 2 divisors, whose sum is σ = 1011330121304. Its totient is φ = 1011330121302.

The previous prime is 1011330121267. The next prime is 1011330121313. The reversal of 1011330121303 is 3031210331101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1011330121303 - 225 = 1011296566871 is a prime.

It is a super-2 number, since 2×10113301213032 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011330121313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505665060651 + 505665060652.

It is an arithmetic number, because the mean of its divisors is an integer number (505665060652).

Almost surely, 21011330121303 is an apocalyptic number.

1011330121303 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011330121303 is an equidigital number, since it uses as much as digits as its factorization.

1011330121303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1011330121303 its reverse (3031210331101), we get a palindrome (4042540452404).

The spelling of 1011330121303 in words is "one trillion, eleven billion, three hundred thirty million, one hundred twenty-one thousand, three hundred three".