Base | Representation |
---|---|
bin | 1001001100101011000111… |
… | …0000111100010100110001 |
3 | 1022210211021201210201022212 |
4 | 2103022301300330110301 |
5 | 2311144102331141032 |
6 | 33302000244141505 |
7 | 2062443610426115 |
oct | 223126160742461 |
9 | 38724251721285 |
10 | 10113335412017 |
11 | 324a050205592 |
12 | 1174047697895 |
13 | 5848b6685bb6 |
14 | 26d6b92a9745 |
15 | 12810ec85bb2 |
hex | 932b1c3c531 |
10113335412017 has 2 divisors, whose sum is σ = 10113335412018. Its totient is φ = 10113335412016.
The previous prime is 10113335411989. The next prime is 10113335412127. The reversal of 10113335412017 is 71021453331101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7102246320016 + 3011089092001 = 2665004^2 + 1735249^2 .
It is a cyclic number.
It is not a de Polignac number, because 10113335412017 - 228 = 10113066976561 is a prime.
It is not a weakly prime, because it can be changed into another prime (10113335712017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056667706008 + 5056667706009.
It is an arithmetic number, because the mean of its divisors is an integer number (5056667706009).
Almost surely, 210113335412017 is an apocalyptic number.
It is an amenable number.
10113335412017 is a deficient number, since it is larger than the sum of its proper divisors (1).
10113335412017 is an equidigital number, since it uses as much as digits as its factorization.
10113335412017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7560, while the sum is 32.
Adding to 10113335412017 its reverse (71021453331101), we get a palindrome (81134788743118).
The spelling of 10113335412017 in words is "ten trillion, one hundred thirteen billion, three hundred thirty-five million, four hundred twelve thousand, seventeen".
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