1011341263 has 2 divisors, whose sum is σ = 1011341264. Its totient is φ = 1011341262.

The previous prime is 1011341249. The next prime is 1011341281. The reversal of 1011341263 is 3621431101.

It is a weak prime.

It is an emirp because it is prime and its reverse (3621431101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1011341263 - 2⁵ = 1011341231 is a prime.

It is a super-3 number, since 3×1011341263³ (a number of 28 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011341363) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505670631 + 505670632.

It is an arithmetic number, because the mean of its divisors is an integer number (505670632).

Almost surely, 2^1011341263 is an apocalyptic number.

1011341263 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011341263 is an equidigital number, since it uses as much as digits as its factorization.

1011341263 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 22.

The square root of 1011341263 is about 31801.5921456772. The cubic root of 1011341263 is about 1003.7662187888.

Adding to 1011341263 its reverse (3621431101), we get a palindrome (4632772364).

The spelling of 1011341263 in words is "one billion, eleven million, three hundred forty-one thousand, two hundred sixty-three".