1011341348047 has 2 divisors, whose sum is σ = 1011341348048. Its totient is φ = 1011341348046.

The previous prime is 1011341347999. The next prime is 1011341348071. The reversal of 1011341348047 is 7408431431101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1011341348047 - 2¹¹ = 1011341345999 is a prime.

It is a super-2 number, since 2×1011341348047² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1011341347997 and 1011341348015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011341346047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505670674023 + 505670674024.

It is an arithmetic number, because the mean of its divisors is an integer number (505670674024).

Almost surely, 2^{1011341348047} is an apocalyptic number.

1011341348047 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011341348047 is an equidigital number, since it uses as much as digits as its factorization.

1011341348047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32256, while the sum is 37.

Adding to 1011341348047 its reverse (7408431431101), we get a palindrome (8419772779148).

The spelling of 1011341348047 in words is "one trillion, eleven billion, three hundred forty-one million, three hundred forty-eight thousand, forty-seven".