Base | Representation |
---|---|
bin | 1001001100101011110100… |
… | …0101101110111011011001 |
3 | 1022210211202222022200200102 |
4 | 2103022331011232323121 |
5 | 2311200000001132140 |
6 | 33302031152345145 |
7 | 2062451405412443 |
oct | 223127505567331 |
9 | 38724688280612 |
10 | 10113525411545 |
11 | 324a138487a96 |
12 | 117409b2451b5 |
13 | 584916b4b35a |
14 | 26d6d6607493 |
15 | 1281217b6e15 |
hex | 932bd16eed9 |
10113525411545 has 32 divisors (see below), whose sum is σ = 12414713702400. Its totient is φ = 7905735886336.
The previous prime is 10113525411533. The next prime is 10113525411571. The reversal of 10113525411545 is 54511452531101.
It is a cyclic number.
It is not a de Polignac number, because 10113525411545 - 238 = 9838647504601 is a prime.
It is a super-3 number, since 3×101135254115453 (a number of 40 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10113525411499 and 10113525411508.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 553035392 + ... + 553053678.
It is an arithmetic number, because the mean of its divisors is an integer number (387959803200).
Almost surely, 210113525411545 is an apocalyptic number.
It is an amenable number.
10113525411545 is a deficient number, since it is larger than the sum of its proper divisors (2301188290855).
10113525411545 is a wasteful number, since it uses less digits than its factorization.
10113525411545 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22057.
The product of its (nonzero) digits is 60000, while the sum is 38.
Adding to 10113525411545 its reverse (54511452531101), we get a palindrome (64624977942646).
The spelling of 10113525411545 in words is "ten trillion, one hundred thirteen billion, five hundred twenty-five million, four hundred eleven thousand, five hundred forty-five".
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