Base | Representation |
---|---|
bin | 1100000011100… |
… | …11001110101001 |
3 | 21001022012111212 |
4 | 12001303032221 |
5 | 201342312043 |
6 | 14011402505 |
7 | 2335431011 |
oct | 601631651 |
9 | 231265455 |
10 | 101135273 |
11 | 520a7478 |
12 | 29a53435 |
13 | 17c50475 |
14 | d608c41 |
15 | 8d2b018 |
hex | 60733a9 |
101135273 has 2 divisors, whose sum is σ = 101135274. Its totient is φ = 101135272.
The previous prime is 101135257. The next prime is 101135297. The reversal of 101135273 is 372531101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 80048809 + 21086464 = 8947^2 + 4592^2 .
It is an emirp because it is prime and its reverse (372531101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 101135273 - 24 = 101135257 is a prime.
It is a super-3 number, since 3×1011352733 (a number of 25 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (101135213) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50567636 + 50567637.
It is an arithmetic number, because the mean of its divisors is an integer number (50567637).
Almost surely, 2101135273 is an apocalyptic number.
It is an amenable number.
101135273 is a deficient number, since it is larger than the sum of its proper divisors (1).
101135273 is an equidigital number, since it uses as much as digits as its factorization.
101135273 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 630, while the sum is 23.
The square root of 101135273 is about 10056.6034524585. The cubic root of 101135273 is about 465.9087681434.
Adding to 101135273 its reverse (372531101), we get a palindrome (473666374).
The spelling of 101135273 in words is "one hundred one million, one hundred thirty-five thousand, two hundred seventy-three".
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