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101135257 is a prime number
BaseRepresentation
bin1100000011100…
…11001110011001
321001022012111021
412001303032121
5201342312012
614011402441
72335430656
oct601631631
9231265437
10101135257
11520a7463
1229a53421
1317c50462
14d608c2d
158d2b007
hex6073399

101135257 has 2 divisors, whose sum is σ = 101135258. Its totient is φ = 101135256.

The previous prime is 101135249. The next prime is 101135273. The reversal of 101135257 is 752531101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 58049161 + 43086096 = 7619^2 + 6564^2 .

It is a cyclic number.

It is not a de Polignac number, because 101135257 - 23 = 101135249 is a prime.

It is a super-3 number, since 3×1011352573 (a number of 25 digits) contains 333 as substring.

It is equal to p5823043 and since 101135257 and 5823043 have the same sum of digits, it is a Honaker prime.

It is not a weakly prime, because it can be changed into another prime (101135297) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50567628 + 50567629.

It is an arithmetic number, because the mean of its divisors is an integer number (50567629).

Almost surely, 2101135257 is an apocalyptic number.

It is an amenable number.

101135257 is a deficient number, since it is larger than the sum of its proper divisors (1).

101135257 is an equidigital number, since it uses as much as digits as its factorization.

101135257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1050, while the sum is 25.

The square root of 101135257 is about 10056.6026569612. The cubic root of 101135257 is about 465.9087435739.

Adding to 101135257 its reverse (752531101), we get a palindrome (853666358).

The spelling of 101135257 in words is "one hundred one million, one hundred thirty-five thousand, two hundred fifty-seven".