101140131341 has 2 divisors, whose sum is σ = 101140131342. Its totient is φ = 101140131340.

The previous prime is 101140131263. The next prime is 101140131413. The reversal of 101140131341 is 143131041101.

Together with next prime (101140131413) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 57732075625 + 43408055716 = 240275^2 + 208346^2 .

It is a cyclic number.

It is not a de Polignac number, because 101140131341 - 2¹⁰ = 101140130317 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101140131641) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50570065670 + 50570065671.

It is an arithmetic number, because the mean of its divisors is an integer number (50570065671).

Almost surely, 2^101140131341 is an apocalyptic number.

It is an amenable number.

101140131341 is a deficient number, since it is larger than the sum of its proper divisors (1).

101140131341 is an equidigital number, since it uses as much as digits as its factorization.

101140131341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 101140131341 its reverse (143131041101), we get a palindrome (244271172442).

The spelling of 101140131341 in words is "one hundred one billion, one hundred forty million, one hundred thirty-one thousand, three hundred forty-one".