10114040976493 has 2 divisors, whose sum is σ = 10114040976494. Its totient is φ = 10114040976492.

The previous prime is 10114040976349. The next prime is 10114040976503. The reversal of 10114040976493 is 39467904041101.

Together with previous prime (10114040976349) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10114040946564 + 29929 = 3180258^2 + 173^2 .

It is a cyclic number.

It is not a de Polignac number, because 10114040976493 - 2²¹ = 10114038879341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10114040970493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5057020488246 + 5057020488247.

It is an arithmetic number, because the mean of its divisors is an integer number (5057020488247).

Almost surely, 2^{10114040976493} is an apocalyptic number.

It is an amenable number.

10114040976493 is a deficient number, since it is larger than the sum of its proper divisors (1).

10114040976493 is an equidigital number, since it uses as much as digits as its factorization.

10114040976493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 653184, while the sum is 49.

The spelling of 10114040976493 in words is "ten trillion, one hundred fourteen billion, forty million, nine hundred seventy-six thousand, four hundred ninety-three".