1011410120213 has 2 divisors, whose sum is σ = 1011410120214. Its totient is φ = 1011410120212.

The previous prime is 1011410120159. The next prime is 1011410120233. The reversal of 1011410120213 is 3120210141101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1008381489124 + 3028631089 = 1004182^2 + 55033^2 .

It is an emirp because it is prime and its reverse (3120210141101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1011410120213 - 2¹⁰ = 1011410119189 is a prime.

It is a super-2 number, since 2×1011410120213² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1011410120191 and 1011410120200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011410120233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505705060106 + 505705060107.

It is an arithmetic number, because the mean of its divisors is an integer number (505705060107).

Almost surely, 2^{1011410120213} is an apocalyptic number.

It is an amenable number.

1011410120213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011410120213 is an equidigital number, since it uses as much as digits as its factorization.

1011410120213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 1011410120213 its reverse (3120210141101), we get a palindrome (4131620261314).

The spelling of 1011410120213 in words is "one trillion, eleven billion, four hundred ten million, one hundred twenty thousand, two hundred thirteen".