Base | Representation |
---|---|
bin | 10010110101101100… |
… | …10001110111110011 |
3 | 222002212111011202012 |
4 | 21122312101313303 |
5 | 131203203104021 |
6 | 4351340313135 |
7 | 505431353642 |
oct | 113266216763 |
9 | 28085434665 |
10 | 10114113011 |
11 | 4320175892 |
12 | 1b632427ab |
13 | c52532972 |
14 | 6bd389359 |
15 | 3e2dee35b |
hex | 25ad91df3 |
10114113011 has 2 divisors, whose sum is σ = 10114113012. Its totient is φ = 10114113010.
The previous prime is 10114112969. The next prime is 10114113019. The reversal of 10114113011 is 11031141101.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10114113011 is a prime.
It is a super-2 number, since 2×101141130112 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10114113019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5057056505 + 5057056506.
It is an arithmetic number, because the mean of its divisors is an integer number (5057056506).
Almost surely, 210114113011 is an apocalyptic number.
10114113011 is a deficient number, since it is larger than the sum of its proper divisors (1).
10114113011 is an equidigital number, since it uses as much as digits as its factorization.
10114113011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 14.
Adding to 10114113011 its reverse (11031141101), we get a palindrome (21145254112).
The spelling of 10114113011 in words is "ten billion, one hundred fourteen million, one hundred thirteen thousand, eleven".
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