1011411301111 has 2 divisors, whose sum is σ = 1011411301112. Its totient is φ = 1011411301110.

The previous prime is 1011411301073. The next prime is 1011411301129. The reversal of 1011411301111 is 1111031141101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1011411301111 - 2¹³ = 1011411292919 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011411301171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505705650555 + 505705650556.

It is an arithmetic number, because the mean of its divisors is an integer number (505705650556).

Almost surely, 2^{1011411301111} is an apocalyptic number.

1011411301111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011411301111 is an equidigital number, since it uses as much as digits as its factorization.

1011411301111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 16.

Adding to 1011411301111 its reverse (1111031141101), we get a palindrome (2122442442212).

The spelling of 1011411301111 in words is "one trillion, eleven billion, four hundred eleven million, three hundred one thousand, one hundred eleven".