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1011413104813 is a prime number
BaseRepresentation
bin11101011011111001110…
…10110011100010101101
310120200122010012012222201
432231330322303202231
5113032333223323223
62052345312541501
7133033521354046
oct16557472634255
93520563165881
101011413104813
1135aa3536a521
12144028251891
13744b69725b7
1436d4a12d8cd
151b498706ead
hexeb7ceb38ad

1011413104813 has 2 divisors, whose sum is σ = 1011413104814. Its totient is φ = 1011413104812.

The previous prime is 1011413104771. The next prime is 1011413104829. The reversal of 1011413104813 is 3184013141101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 804531859849 + 206881244964 = 896957^2 + 454842^2 .

It is a cyclic number.

It is not a de Polignac number, because 1011413104813 - 225 = 1011379550381 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011413104873) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505706552406 + 505706552407.

It is an arithmetic number, because the mean of its divisors is an integer number (505706552407).

Almost surely, 21011413104813 is an apocalyptic number.

It is an amenable number.

1011413104813 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011413104813 is an equidigital number, since it uses as much as digits as its factorization.

1011413104813 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 28.

Adding to 1011413104813 its reverse (3184013141101), we get a palindrome (4195426245914).

The spelling of 1011413104813 in words is "one trillion, eleven billion, four hundred thirteen million, one hundred four thousand, eight hundred thirteen".