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101143131413 is a prime number
BaseRepresentation
bin101111000110010011…
…0011011010100010101
3100200001211122102202012
41132030212123110111
53124120120201123
6114244200154005
710210264301102
oct1361446332425
9320054572665
10101143131413
113999272a705
1217728768905
1396cb5b236c
144c76bc9aa9
15296e790378
hex178c99b515

101143131413 has 2 divisors, whose sum is σ = 101143131414. Its totient is φ = 101143131412.

The previous prime is 101143131409. The next prime is 101143131449. The reversal of 101143131413 is 314131341101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 101138628529 + 4502884 = 318023^2 + 2122^2 .

It is a cyclic number.

It is not a de Polignac number, because 101143131413 - 22 = 101143131409 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101143131013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50571565706 + 50571565707.

It is an arithmetic number, because the mean of its divisors is an integer number (50571565707).

Almost surely, 2101143131413 is an apocalyptic number.

It is an amenable number.

101143131413 is a deficient number, since it is larger than the sum of its proper divisors (1).

101143131413 is an equidigital number, since it uses as much as digits as its factorization.

101143131413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 101143131413 its reverse (314131341101), we get a palindrome (415274472514).

The spelling of 101143131413 in words is "one hundred one billion, one hundred forty-three million, one hundred thirty-one thousand, four hundred thirteen".