1011431411 has 2 divisors, whose sum is σ = 1011431412. Its totient is φ = 1011431410.

The previous prime is 1011431387. The next prime is 1011431413. The reversal of 1011431411 is 1141341101.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1011431411 is a prime.

Together with 1011431413, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1011431411.

It is not a weakly prime, because it can be changed into another prime (1011431413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505715705 + 505715706.

It is an arithmetic number, because the mean of its divisors is an integer number (505715706).

Almost surely, 2^1011431411 is an apocalyptic number.

1011431411 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011431411 is an equidigital number, since it uses as much as digits as its factorization.

1011431411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

The square root of 1011431411 is about 31803.0094645145. The cubic root of 1011431411 is about 1003.7960421637.

Adding to 1011431411 its reverse (1141341101), we get a palindrome (2152772512).

The spelling of 1011431411 in words is "one billion, eleven million, four hundred thirty-one thousand, four hundred eleven".