1011442221313 has 2 divisors, whose sum is σ = 1011442221314. Its totient is φ = 1011442221312.

The previous prime is 1011442221263. The next prime is 1011442221343. The reversal of 1011442221313 is 3131222441101.

1011442221313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 802183548609 + 209258672704 = 895647^2 + 457448^2 .

It is an emirp because it is prime and its reverse (3131222441101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1011442221313 - 2²⁹ = 1010905350401 is a prime.

It is a super-3 number, since 3×1011442221313³ (a number of 37 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (1011442221343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505721110656 + 505721110657.

It is an arithmetic number, because the mean of its divisors is an integer number (505721110657).

Almost surely, 2^{1011442221313} is an apocalyptic number.

It is an amenable number.

1011442221313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011442221313 is an equidigital number, since it uses as much as digits as its factorization.

1011442221313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1011442221313 its reverse (3131222441101), we get a palindrome (4142664662414).

The spelling of 1011442221313 in words is "one trillion, eleven billion, four hundred forty-two million, two hundred twenty-one thousand, three hundred thirteen".