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10114535105113 is a prime number
BaseRepresentation
bin1001001100101111100101…
…0001011010001001011001
31022210221101100020102212111
42103023321101122021121
52311204031441330423
633302315301512321
72062515415565455
oct223137121321131
938727340212774
1010114535105113
11324a60642178a
1211743214126a1
13584a480a077a
1426d790759665
1512818026060d
hex932f945a259

10114535105113 has 2 divisors, whose sum is σ = 10114535105114. Its totient is φ = 10114535105112.

The previous prime is 10114535105089. The next prime is 10114535105137. The reversal of 10114535105113 is 31150153541101.

It is a balanced prime because it is at equal distance from previous prime (10114535105089) and next prime (10114535105137).

It can be written as a sum of positive squares in only one way, i.e., 6649606014489 + 3464929090624 = 2578683^2 + 1861432^2 .

It is a cyclic number.

It is not a de Polignac number, because 10114535105113 - 237 = 9977096151641 is a prime.

It is not a weakly prime, because it can be changed into another prime (10114535105153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5057267552556 + 5057267552557.

It is an arithmetic number, because the mean of its divisors is an integer number (5057267552557).

Almost surely, 210114535105113 is an apocalyptic number.

It is an amenable number.

10114535105113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10114535105113 is an equidigital number, since it uses as much as digits as its factorization.

10114535105113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4500, while the sum is 31.

Adding to 10114535105113 its reverse (31150153541101), we get a palindrome (41264688646214).

The spelling of 10114535105113 in words is "ten trillion, one hundred fourteen billion, five hundred thirty-five million, one hundred five thousand, one hundred thirteen".