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101151322091 is a prime number
BaseRepresentation
bin101111000110100010…
…1101010111111101011
3100200002102001120020122
41132031011222333223
53124124214301331
6114245051513455
710210424023451
oct1361505527753
9320072046218
10101151322091
1139997314466
121772b45888b
1397001bc511
144c77d1c9d1
15297035c17b
hex178d16afeb

101151322091 has 2 divisors, whose sum is σ = 101151322092. Its totient is φ = 101151322090.

The previous prime is 101151322057. The next prime is 101151322093. The reversal of 101151322091 is 190223151101.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-101151322091 is a prime.

It is a super-2 number, since 2×1011513220912 (a number of 23 digits) contains 22 as substring.

Together with 101151322093, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 101151322091.

It is not a weakly prime, because it can be changed into another prime (101151322093) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50575661045 + 50575661046.

It is an arithmetic number, because the mean of its divisors is an integer number (50575661046).

Almost surely, 2101151322091 is an apocalyptic number.

101151322091 is a deficient number, since it is larger than the sum of its proper divisors (1).

101151322091 is an equidigital number, since it uses as much as digits as its factorization.

101151322091 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 26.

Adding to 101151322091 its reverse (190223151101), we get a palindrome (291374473192).

The spelling of 101151322091 in words is "one hundred one billion, one hundred fifty-one million, three hundred twenty-two thousand, ninety-one".