Base | Representation |
---|---|
bin | 10010110110010011… |
… | …01000110111100111 |
3 | 222010020001000020122 |
4 | 21123021220313213 |
5 | 131211003003233 |
6 | 4352041152155 |
7 | 505522451444 |
oct | 113311506747 |
9 | 28106030218 |
10 | 10119187943 |
11 | 4323021747 |
12 | 1b64a8b65b |
13 | c535bb897 |
14 | 6bdd0a9cb |
15 | 3e35a2d98 |
hex | 25b268de7 |
10119187943 has 2 divisors, whose sum is σ = 10119187944. Its totient is φ = 10119187942.
The previous prime is 10119187913. The next prime is 10119187957. The reversal of 10119187943 is 34978191101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10119187943 - 212 = 10119183847 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10119187894 and 10119187903.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10119187913) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5059593971 + 5059593972.
It is an arithmetic number, because the mean of its divisors is an integer number (5059593972).
Almost surely, 210119187943 is an apocalyptic number.
10119187943 is a deficient number, since it is larger than the sum of its proper divisors (1).
10119187943 is an equidigital number, since it uses as much as digits as its factorization.
10119187943 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54432, while the sum is 44.
The spelling of 10119187943 in words is "ten billion, one hundred nineteen million, one hundred eighty-seven thousand, nine hundred forty-three".
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