Base | Representation |
---|---|
bin | 10010110110010011… |
… | …11000010010001011 |
3 | 222010020011012212011 |
4 | 21123021320102023 |
5 | 131211012013313 |
6 | 4352042400351 |
7 | 505523133514 |
oct | 113311702213 |
9 | 28106135764 |
10 | 10119251083 |
11 | 4323065127 |
12 | 1b64b000b7 |
13 | c53611546 |
14 | 6bdd25a0b |
15 | 3e35b693d |
hex | 25b27848b |
10119251083 has 2 divisors, whose sum is σ = 10119251084. Its totient is φ = 10119251082.
The previous prime is 10119251081. The next prime is 10119251137. The reversal of 10119251083 is 38015291101.
10119251083 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10119251083 - 21 = 10119251081 is a prime.
Together with 10119251081, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (10119251081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5059625541 + 5059625542.
It is an arithmetic number, because the mean of its divisors is an integer number (5059625542).
Almost surely, 210119251083 is an apocalyptic number.
10119251083 is a deficient number, since it is larger than the sum of its proper divisors (1).
10119251083 is an equidigital number, since it uses as much as digits as its factorization.
10119251083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 31.
The spelling of 10119251083 in words is "ten billion, one hundred nineteen million, two hundred fifty-one thousand, eighty-three".
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