1011999893 has 2 divisors, whose sum is σ = 1011999894. Its totient is φ = 1011999892.

The previous prime is 1011999887. The next prime is 1011999941. The reversal of 1011999893 is 3989991101.

1011999893 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 983888689 + 28111204 = 31367^2 + 5302^2 .

It is a cyclic number.

It is not a de Polignac number, because 1011999893 - 2²⁴ = 995222677 is a prime.

It is a super-2 number, since 2×1011999893² = 2048287566864022898, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011999853) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505999946 + 505999947.

It is an arithmetic number, because the mean of its divisors is an integer number (505999947).

Almost surely, 2^1011999893 is an apocalyptic number.

It is an amenable number.

1011999893 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011999893 is an equidigital number, since it uses as much as digits as its factorization.

1011999893 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 157464, while the sum is 50.

The square root of 1011999893 is about 31811.9457594156. The cubic root of 1011999893 is about 1003.9840704366.

The spelling of 1011999893 in words is "one billion, eleven million, nine hundred ninety-nine thousand, eight hundred ninety-three".