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101200000093 is a prime number
BaseRepresentation
bin101111000111111111…
…1010111010001011101
3100200012210122122220121
41132033333113101131
53124224200000333
6114253551114541
710211554544023
oct1361777272135
9320183578817
10101200000093
1139a11841a15
1217743812a51
13970a303c7a
144c80590713
15297477532d
hex178ffd745d

101200000093 has 2 divisors, whose sum is σ = 101200000094. Its totient is φ = 101200000092.

The previous prime is 101200000049. The next prime is 101200000129. The reversal of 101200000093 is 390000002101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 70189494489 + 31010505604 = 264933^2 + 176098^2 .

It is an emirp because it is prime and its reverse (390000002101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101200000093 - 29 = 101199999581 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101200000193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50600000046 + 50600000047.

It is an arithmetic number, because the mean of its divisors is an integer number (50600000047).

Almost surely, 2101200000093 is an apocalyptic number.

It is an amenable number.

101200000093 is a deficient number, since it is larger than the sum of its proper divisors (1).

101200000093 is an equidigital number, since it uses as much as digits as its factorization.

101200000093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 101200000093 its reverse (390000002101), we get a palindrome (491200002194).

The spelling of 101200000093 in words is "one hundred one billion, two hundred million, ninety-three", and thus it is an aban number.