Base | Representation |
---|---|
bin | 1001001101000011111110… |
… | …1010101101011001100111 |
3 | 1022211110111222022022100222 |
4 | 2103100333222231121213 |
5 | 2311301240321004431 |
6 | 33305022515354555 |
7 | 2063101211061326 |
oct | 223207752553147 |
9 | 38743458268328 |
10 | 10120011109991 |
11 | 3251966497252 |
12 | 11753ab2b2a5b |
13 | 58540b732743 |
14 | 26db4db280bd |
15 | 1283a0d9057b |
hex | 9343faad667 |
10120011109991 has 2 divisors, whose sum is σ = 10120011109992. Its totient is φ = 10120011109990.
The previous prime is 10120011109987. The next prime is 10120011110003. The reversal of 10120011109991 is 19990111002101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10120011109991 - 22 = 10120011109987 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10120011109961) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060005554995 + 5060005554996.
It is an arithmetic number, because the mean of its divisors is an integer number (5060005554996).
Almost surely, 210120011109991 is an apocalyptic number.
10120011109991 is a deficient number, since it is larger than the sum of its proper divisors (1).
10120011109991 is an equidigital number, since it uses as much as digits as its factorization.
10120011109991 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1458, while the sum is 35.
The spelling of 10120011109991 in words is "ten trillion, one hundred twenty billion, eleven million, one hundred nine thousand, nine hundred ninety-one".
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