10120011323 has 2 divisors, whose sum is σ = 10120011324. Its totient is φ = 10120011322.

The previous prime is 10120011313. The next prime is 10120011337. The reversal of 10120011323 is 32311002101.

It is an a-pointer prime, because the next prime (10120011337) can be obtained adding 10120011323 to its sum of digits (14).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10120011323 - 2¹⁴ = 10119994939 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10120011298 and 10120011307.

It is not a weakly prime, because it can be changed into another prime (10120011313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060005661 + 5060005662.

It is an arithmetic number, because the mean of its divisors is an integer number (5060005662).

Almost surely, 2^10120011323 is an apocalyptic number.

10120011323 is a deficient number, since it is larger than the sum of its proper divisors (1).

10120011323 is an equidigital number, since it uses as much as digits as its factorization.

10120011323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 10120011323 its reverse (32311002101), we get a palindrome (42431013424).

The spelling of 10120011323 in words is "ten billion, one hundred twenty million, eleven thousand, three hundred twenty-three".