Search a number
-
+
10120021212013 is a prime number
BaseRepresentation
bin1001001101000100000001…
…0001001111101101101101
31022211110112200022112201221
42103101000101033231231
52311301300412241023
633305023520103341
72063101362664306
oct223210021175555
938743480275657
1010120021212013
113251971167029
1211753b2764b51
1358541085b87b
1426db511d77ad
151283a1bd885d
hex9344044fb6d

10120021212013 has 2 divisors, whose sum is σ = 10120021212014. Its totient is φ = 10120021212012.

The previous prime is 10120021211969. The next prime is 10120021212023. The reversal of 10120021212013 is 31021212002101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8817348237604 + 1302672974409 = 2969402^2 + 1141347^2 .

It is a cyclic number.

It is not a de Polignac number, because 10120021212013 - 217 = 10120021080941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10120021212023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060010606006 + 5060010606007.

It is an arithmetic number, because the mean of its divisors is an integer number (5060010606007).

Almost surely, 210120021212013 is an apocalyptic number.

It is an amenable number.

10120021212013 is a deficient number, since it is larger than the sum of its proper divisors (1).

10120021212013 is an equidigital number, since it uses as much as digits as its factorization.

10120021212013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 10120021212013 its reverse (31021212002101), we get a palindrome (41141233214114).

The spelling of 10120021212013 in words is "ten trillion, one hundred twenty billion, twenty-one million, two hundred twelve thousand, thirteen".