Base | Representation |
---|---|
bin | 11101011101000000001… |
… | …01100101001110001111 |
3 | 10120202011020102201112201 |
4 | 32232200011211032033 |
5 | 113040040300213203 |
6 | 2052524031142331 |
7 | 133054244456602 |
oct | 16564005451617 |
9 | 3522136381481 |
10 | 1012003132303 |
11 | 360208426949 |
12 | 1441719749a7 |
13 | 7457bc88ca7 |
14 | 36da463c339 |
15 | 1b4d0404e1d |
hex | eba016538f |
1012003132303 has 2 divisors, whose sum is σ = 1012003132304. Its totient is φ = 1012003132302.
The previous prime is 1012003132297. The next prime is 1012003132331. The reversal of 1012003132303 is 3032313002101.
1012003132303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (3032313002101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1012003132303 - 25 = 1012003132271 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1012003132103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506001566151 + 506001566152.
It is an arithmetic number, because the mean of its divisors is an integer number (506001566152).
Almost surely, 21012003132303 is an apocalyptic number.
1012003132303 is a deficient number, since it is larger than the sum of its proper divisors (1).
1012003132303 is an equidigital number, since it uses as much as digits as its factorization.
1012003132303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 1012003132303 its reverse (3032313002101), we get a palindrome (4044316134404).
The spelling of 1012003132303 in words is "one trillion, twelve billion, three million, one hundred thirty-two thousand, three hundred three".
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