Base | Representation |
---|---|
bin | 101111001000000001… |
… | …1010000100011011011 |
3 | 100200012212120112112102 |
4 | 1132100003100203123 |
5 | 3124224430134042 |
6 | 114254025034015 |
7 | 10211566325612 |
oct | 1362003204333 |
9 | 320185515472 |
10 | 101201021147 |
11 | 39a1237a066 |
12 | 1774402590b |
13 | 970a5a0945 |
14 | 4c80778879 |
15 | 29748c7b32 |
hex | 17900d08db |
101201021147 has 2 divisors, whose sum is σ = 101201021148. Its totient is φ = 101201021146.
The previous prime is 101201021101. The next prime is 101201021183. The reversal of 101201021147 is 741120102101.
It is a strong prime.
It is an emirp because it is prime and its reverse (741120102101) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-101201021147 is a prime.
It is not a weakly prime, because it can be changed into another prime (101201021197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50600510573 + 50600510574.
It is an arithmetic number, because the mean of its divisors is an integer number (50600510574).
Almost surely, 2101201021147 is an apocalyptic number.
101201021147 is a deficient number, since it is larger than the sum of its proper divisors (1).
101201021147 is an equidigital number, since it uses as much as digits as its factorization.
101201021147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 20.
Adding to 101201021147 its reverse (741120102101), we get a palindrome (842321123248).
The spelling of 101201021147 in words is "one hundred one billion, two hundred one million, twenty-one thousand, one hundred forty-seven".
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