1012011000313 has 2 divisors, whose sum is σ = 1012011000314. Its totient is φ = 1012011000312.

The previous prime is 1012011000311. The next prime is 1012011000317. The reversal of 1012011000313 is 3130001102101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 985439392249 + 26571608064 = 992693^2 + 163008^2 .

It is a cyclic number.

It is not a de Polignac number, because 1012011000313 - 2¹ = 1012011000311 is a prime.

Together with 1012011000311, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1012011000293 and 1012011000302.

It is not a weakly prime, because it can be changed into another prime (1012011000311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506005500156 + 506005500157.

It is an arithmetic number, because the mean of its divisors is an integer number (506005500157).

Almost surely, 2^{1012011000313} is an apocalyptic number.

It is an amenable number.

1012011000313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1012011000313 is an equidigital number, since it uses as much as digits as its factorization.

1012011000313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1012011000313 its reverse (3130001102101), we get a palindrome (4142012102414).

The spelling of 1012011000313 in words is "one trillion, twelve billion, eleven million, three hundred thirteen", and thus it is an aban number.