Base | Representation |
---|---|
bin | 101111001000000001… |
… | …1100100010100110011 |
3 | 100200012212201122121211 |
4 | 1132100003210110303 |
5 | 3124224440232011 |
6 | 114254030500551 |
7 | 10211600113663 |
oct | 1362003442463 |
9 | 320185648554 |
10 | 101201102131 |
11 | 39a12424998 |
12 | 17744064757 |
13 | 970a5cb76c |
14 | 4c8079a1a3 |
15 | 29748e1b21 |
hex | 17900e4533 |
101201102131 has 2 divisors, whose sum is σ = 101201102132. Its totient is φ = 101201102130.
The previous prime is 101201102117. The next prime is 101201102213. The reversal of 101201102131 is 131201102101.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (131201102101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 101201102131 - 211 = 101201100083 is a prime.
It is a super-2 number, since 2×1012011021312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (101201109131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50600551065 + 50600551066.
It is an arithmetic number, because the mean of its divisors is an integer number (50600551066).
Almost surely, 2101201102131 is an apocalyptic number.
101201102131 is a deficient number, since it is larger than the sum of its proper divisors (1).
101201102131 is an equidigital number, since it uses as much as digits as its factorization.
101201102131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 101201102131 its reverse (131201102101), we get a palindrome (232402204232).
The spelling of 101201102131 in words is "one hundred one billion, two hundred one million, one hundred two thousand, one hundred thirty-one".
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