Base | Representation |
---|---|
bin | 10010110110011010… |
… | …01011010100101111 |
3 | 222010021210010121201 |
4 | 21123031023110233 |
5 | 131211222144003 |
6 | 4352113110331 |
7 | 505533363631 |
oct | 113315132457 |
9 | 28107703551 |
10 | 10120115503 |
11 | 43235a5623 |
12 | 1b652583a7 |
13 | c53854b34 |
14 | 6c00aca51 |
15 | 3e36d7b1d |
hex | 25b34b52f |
10120115503 has 2 divisors, whose sum is σ = 10120115504. Its totient is φ = 10120115502.
The previous prime is 10120115497. The next prime is 10120115531. The reversal of 10120115503 is 30551102101.
10120115503 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10120115503 - 229 = 9583244591 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10120115003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060057751 + 5060057752.
It is an arithmetic number, because the mean of its divisors is an integer number (5060057752).
Almost surely, 210120115503 is an apocalyptic number.
10120115503 is a deficient number, since it is larger than the sum of its proper divisors (1).
10120115503 is an equidigital number, since it uses as much as digits as its factorization.
10120115503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 150, while the sum is 19.
Adding to 10120115503 its reverse (30551102101), we get a palindrome (40671217604).
The spelling of 10120115503 in words is "ten billion, one hundred twenty million, one hundred fifteen thousand, five hundred three".
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