10120120001993 has 2 divisors, whose sum is σ = 10120120001994. Its totient is φ = 10120120001992.

The previous prime is 10120120001939. The next prime is 10120120002029. The reversal of 10120120001993 is 39910002102101.

Together with previous prime (10120120001939) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8113171779769 + 2006948222224 = 2848363^2 + 1416668^2 .

It is an emirp because it is prime and its reverse (39910002102101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10120120001993 - 2¹⁴ = 10120119985609 is a prime.

It is not a weakly prime, because it can be changed into another prime (10120120004993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060060000996 + 5060060000997.

It is an arithmetic number, because the mean of its divisors is an integer number (5060060000997).

Almost surely, 2^{10120120001993} is an apocalyptic number.

It is an amenable number.

10120120001993 is a deficient number, since it is larger than the sum of its proper divisors (1).

10120120001993 is an equidigital number, since it uses as much as digits as its factorization.

10120120001993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 29.

The spelling of 10120120001993 in words is "ten trillion, one hundred twenty billion, one hundred twenty million, one thousand, nine hundred ninety-three".