Search a number
-
+
1012012010983 is a prime number
BaseRepresentation
bin11101011101000001001…
…11011100110111100111
310120202011212010210210201
432232200213130313213
5113040100033322413
62052524545331331
7133054413106141
oct16564047346747
93522155123721
101012012010983
113602124405a6
12144174936b47
1374580a7734c
1436da58adc91
151b4d10aa9dd
hexeba09dcde7

1012012010983 has 2 divisors, whose sum is σ = 1012012010984. Its totient is φ = 1012012010982.

The previous prime is 1012012010963. The next prime is 1012012010987. The reversal of 1012012010983 is 3890102102101.

It is a strong prime.

It is an emirp because it is prime and its reverse (3890102102101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1012012010983 - 237 = 874573057511 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1012012010987) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506006005491 + 506006005492.

It is an arithmetic number, because the mean of its divisors is an integer number (506006005492).

Almost surely, 21012012010983 is an apocalyptic number.

1012012010983 is a deficient number, since it is larger than the sum of its proper divisors (1).

1012012010983 is an equidigital number, since it uses as much as digits as its factorization.

1012012010983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 28.

The spelling of 1012012010983 in words is "one trillion, twelve billion, twelve million, ten thousand, nine hundred eighty-three".