1012012011041 has 2 divisors, whose sum is σ = 1012012011042. Its totient is φ = 1012012011040.

The previous prime is 1012012010993. The next prime is 1012012011079. The reversal of 1012012011041 is 1401102102101.

1012012011041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 862297960000 + 149714051041 = 928600^2 + 386929^2 .

It is a cyclic number.

It is not a de Polignac number, because 1012012011041 - 2¹⁰ = 1012012010017 is a prime.

It is not a weakly prime, because it can be changed into another prime (1012012011641) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506006005520 + 506006005521.

It is an arithmetic number, because the mean of its divisors is an integer number (506006005521).

Almost surely, 2^{1012012011041} is an apocalyptic number.

It is an amenable number.

1012012011041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1012012011041 is an equidigital number, since it uses as much as digits as its factorization.

1012012011041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 1012012011041 its reverse (1401102102101), we get a palindrome (2413114113142).

The spelling of 1012012011041 in words is "one trillion, twelve billion, twelve million, eleven thousand, forty-one".