1012012010993 has 2 divisors, whose sum is σ = 1012012010994. Its totient is φ = 1012012010992.

The previous prime is 1012012010987. The next prime is 1012012011041. The reversal of 1012012010993 is 3990102102101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 909568486369 + 102443524624 = 953713^2 + 320068^2 .

It is a cyclic number.

It is not a de Polignac number, because 1012012010993 - 2²² = 1012007816689 is a prime.

It is not a weakly prime, because it can be changed into another prime (1012012010923) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506006005496 + 506006005497.

It is an arithmetic number, because the mean of its divisors is an integer number (506006005497).

Almost surely, 2^{1012012010993} is an apocalyptic number.

It is an amenable number.

1012012010993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1012012010993 is an equidigital number, since it uses as much as digits as its factorization.

1012012010993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 29.

The spelling of 1012012010993 in words is "one trillion, twelve billion, twelve million, ten thousand, nine hundred ninety-three".