Base | Representation |
---|---|
bin | 101111001000000001… |
… | …1111101010011011101 |
3 | 100200012212220211222020 |
4 | 1132100003331103131 |
5 | 3124230002020240 |
6 | 114254033010353 |
7 | 10211601021165 |
oct | 1362003752335 |
9 | 320185824866 |
10 | 101201204445 |
11 | 39a12494850 |
12 | 177440b39b9 |
13 | 970a6361c3 |
14 | 4c807c55a5 |
15 | 29749120d0 |
hex | 17900fd4dd |
101201204445 has 64 divisors (see below), whose sum is σ = 182841753600. Its totient is φ = 47347139840.
The previous prime is 101201204413. The next prime is 101201204483. The reversal of 101201204445 is 544402102101.
It is not a de Polignac number, because 101201204445 - 25 = 101201204413 is a prime.
It is a super-2 number, since 2×1012012044452 (a number of 23 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 9579076 + ... + 9589634.
It is an arithmetic number, because the mean of its divisors is an integer number (2856902400).
Almost surely, 2101201204445 is an apocalyptic number.
101201204445 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
101201204445 is a deficient number, since it is larger than the sum of its proper divisors (81640549155).
101201204445 is a wasteful number, since it uses less digits than its factorization.
101201204445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12610.
The product of its (nonzero) digits is 1280, while the sum is 24.
Adding to 101201204445 its reverse (544402102101), we get a palindrome (645603306546).
The spelling of 101201204445 in words is "one hundred one billion, two hundred one million, two hundred four thousand, four hundred forty-five".
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