Search a number
-
+
101201210111983 is a prime number
BaseRepresentation
bin10111000000101010111110…
…001011011111011111101111
3111021022202000100001200211111
4113000222332023133133233
5101231040034242040413
6555123105532132451
730213355220500462
oct2700527613373757
9437282010050744
10101201210111983
112a278212886313
12b425580607127
134461305355937
141adc243d3d2d9
15ba7720841d3d
hex5c0abe2df7ef

101201210111983 has 2 divisors, whose sum is σ = 101201210111984. Its totient is φ = 101201210111982.

The previous prime is 101201210111951. The next prime is 101201210112007. The reversal of 101201210111983 is 389111012102101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101201210111983 - 25 = 101201210111951 is a prime.

It is a super-2 number, since 2×1012012101119832 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101201210811983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50600605055991 + 50600605055992.

It is an arithmetic number, because the mean of its divisors is an integer number (50600605055992).

Almost surely, 2101201210111983 is an apocalyptic number.

101201210111983 is a deficient number, since it is larger than the sum of its proper divisors (1).

101201210111983 is an equidigital number, since it uses as much as digits as its factorization.

101201210111983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 31.

The spelling of 101201210111983 in words is "one hundred one trillion, two hundred one billion, two hundred ten million, one hundred eleven thousand, nine hundred eighty-three".