Base | Representation |
---|---|
bin | 10111000000101010111110… |
… | …001111101001001001111000 |
3 | 111021022202000102002222110212 |
4 | 113000222332033221021320 |
5 | 101231040040031400440 |
6 | 555123110011330252 |
7 | 30213355232652053 |
oct | 2700527617511170 |
9 | 437282012088425 |
10 | 101201211200120 |
11 | 2a2782134598a9 |
12 | b425580a50988 |
13 | 4461305646cc5 |
14 | 1adc244143a9a |
15 | ba77209a9465 |
hex | 5c0abe3e9278 |
101201211200120 has 16 divisors (see below), whose sum is σ = 227702725200360. Its totient is φ = 40480484480032.
The previous prime is 101201211200071. The next prime is 101201211200147. The reversal of 101201211200120 is 21002112102101.
It is a junction number, because it is equal to n+sod(n) for n = 101201211200095 and 101201211200104.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1265015139962 + ... + 1265015140041.
Almost surely, 2101201211200120 is an apocalyptic number.
101201211200120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
101201211200120 is an abundant number, since it is smaller than the sum of its proper divisors (126501514000240).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
101201211200120 is a wasteful number, since it uses less digits than its factorization.
101201211200120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2530030280014 (or 2530030280010 counting only the distinct ones).
The product of its (nonzero) digits is 16, while the sum is 14.
Adding to 101201211200120 its reverse (21002112102101), we get a palindrome (122203323302221).
The spelling of 101201211200120 in words is "one hundred one trillion, two hundred one billion, two hundred eleven million, two hundred thousand, one hundred twenty".
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