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101201211220217 is a prime number
BaseRepresentation
bin10111000000101010111110…
…001111101110000011111001
3111021022202000102011000001012
4113000222332033232003321
5101231040040033021332
6555123110012003305
730213355233064463
oct2700527617560371
9437282012130035
10101201211220217
112a278213472a09
12b425580a60535
1344613056531b4
141adc24414b133
15ba77209b03b2
hex5c0abe3ee0f9

101201211220217 has 2 divisors, whose sum is σ = 101201211220218. Its totient is φ = 101201211220216.

The previous prime is 101201211220211. The next prime is 101201211220237. The reversal of 101201211220217 is 712022112102101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 96276344826601 + 4924866393616 = 9812051^2 + 2219204^2 .

It is a cyclic number.

It is not a de Polignac number, because 101201211220217 - 28 = 101201211219961 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101201211220192 and 101201211220201.

It is not a weakly prime, because it can be changed into another prime (101201211220211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50600605610108 + 50600605610109.

It is an arithmetic number, because the mean of its divisors is an integer number (50600605610109).

Almost surely, 2101201211220217 is an apocalyptic number.

It is an amenable number.

101201211220217 is a deficient number, since it is larger than the sum of its proper divisors (1).

101201211220217 is an equidigital number, since it uses as much as digits as its factorization.

101201211220217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 224, while the sum is 23.

Adding to 101201211220217 its reverse (712022112102101), we get a palindrome (813223323322318).

The spelling of 101201211220217 in words is "one hundred one trillion, two hundred one billion, two hundred eleven million, two hundred twenty thousand, two hundred seventeen".