101201212010120 has 128 divisors (see below), whose sum is σ = 242417893305600. Its totient is φ = 37914125184000.

The previous prime is 101201212010081. The next prime is 101201212010137. The reversal of 101201212010120 is 21010212102101.

101201212010120 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 101201212010095 and 101201212010104.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 50992805 + ... + 52940235.

It is an arithmetic number, because the mean of its divisors is an integer number (1893889791450).

Almost surely, 2^{101201212010120} is an apocalyptic number.

101201212010120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 101201212010120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (121208946652800).

101201212010120 is an abundant number, since it is smaller than the sum of its proper divisors (141216681295480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101201212010120 is a wasteful number, since it uses less digits than its factorization.

101201212010120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1948239 (or 1948235 counting only the distinct ones).

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 101201212010120 its reverse (21010212102101), we get a palindrome (122211424112221).

The spelling of 101201212010120 in words is "one hundred one trillion, two hundred one billion, two hundred twelve million, ten thousand, one hundred twenty".