Base | Representation |
---|---|
bin | 1001001101000100011000… |
… | …1111001010110110111010 |
3 | 1022211110210122201010100101 |
4 | 2103101012033022312322 |
5 | 2311302002030044010 |
6 | 33305041454030014 |
7 | 2063104016663626 |
oct | 223210617126672 |
9 | 38743718633311 |
10 | 10120121331130 |
11 | 3251a12729aa8 |
12 | 11754201a830a |
13 | 585428514655 |
14 | 26db6061a186 |
15 | 1283aa8b373a |
hex | 934463cadba |
10120121331130 has 64 divisors (see below), whose sum is σ = 18315393719040. Its totient is φ = 4026080088576.
The previous prime is 10120121331101. The next prime is 10120121331167. The reversal of 10120121331130 is 3113312102101.
10120121331130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 10120121331098 and 10120121331107.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3486089259 + ... + 3486092161.
It is an arithmetic number, because the mean of its divisors is an integer number (286178026860).
Almost surely, 210120121331130 is an apocalyptic number.
10120121331130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
10120121331130 is a deficient number, since it is larger than the sum of its proper divisors (8195272387910).
10120121331130 is a wasteful number, since it uses less digits than its factorization.
10120121331130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5335.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 10120121331130 its reverse (3113312102101), we get a palindrome (13233433433231).
The spelling of 10120121331130 in words is "ten trillion, one hundred twenty billion, one hundred twenty-one million, three hundred thirty-one thousand, one hundred thirty".
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