Base | Representation |
---|---|
bin | 11101011101000001010… |
… | …00001011100000011011 |
3 | 10120202011212111111211211 |
4 | 32232200220023200123 |
5 | 113040100110431021 |
6 | 2052524553403551 |
7 | 133054414533106 |
oct | 16564050134033 |
9 | 3522155444754 |
10 | 1012012202011 |
11 | 360212561078 |
12 | 144174a095b7 |
13 | 74580b13295 |
14 | 36da591d73d |
15 | 1b4d10e73e1 |
hex | eba0a0b81b |
1012012202011 has 2 divisors, whose sum is σ = 1012012202012. Its totient is φ = 1012012202010.
The previous prime is 1012012202009. The next prime is 1012012202023. The reversal of 1012012202011 is 1102022102101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1012012202011 - 21 = 1012012202009 is a prime.
Together with 1012012202009, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 1012012201982 and 1012012202000.
It is not a weakly prime, because it can be changed into another prime (1012012206011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506006101005 + 506006101006.
It is an arithmetic number, because the mean of its divisors is an integer number (506006101006).
Almost surely, 21012012202011 is an apocalyptic number.
1012012202011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1012012202011 is an equidigital number, since it uses as much as digits as its factorization.
1012012202011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 1012012202011 its reverse (1102022102101), we get a palindrome (2114034304112).
The spelling of 1012012202011 in words is "one trillion, twelve billion, twelve million, two hundred two thousand, eleven".
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