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101201222022013 is a prime number
BaseRepresentation
bin10111000000101010111110…
…111000111011001101111101
3111021022202001011110210022201
4113000222332320323031331
5101231040100314201023
6555123111035311501
730213355423643551
oct2700527670731575
9437282034423281
10101201222022013
112a278219580513
12b4255845ab591
1344613079659a9
141adc24575d861
15ba77218e5bad
hex5c0abee3b37d

101201222022013 has 2 divisors, whose sum is σ = 101201222022014. Its totient is φ = 101201222022012.

The previous prime is 101201222021969. The next prime is 101201222022049. The reversal of 101201222022013 is 310220222102101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 76383020308644 + 24818201713369 = 8739738^2 + 4981787^2 .

It is an emirp because it is prime and its reverse (310220222102101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101201222022013 - 213 = 101201222013821 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101201222022413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50600611011006 + 50600611011007.

It is an arithmetic number, because the mean of its divisors is an integer number (50600611011007).

Almost surely, 2101201222022013 is an apocalyptic number.

It is an amenable number.

101201222022013 is a deficient number, since it is larger than the sum of its proper divisors (1).

101201222022013 is an equidigital number, since it uses as much as digits as its factorization.

101201222022013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 101201222022013 its reverse (310220222102101), we get a palindrome (411421444124114).

The spelling of 101201222022013 in words is "one hundred one trillion, two hundred one billion, two hundred twenty-two million, twenty-two thousand, thirteen".